Most Important Selected Qs for JEE AdvancedMathematicsEllipse

If (5,12) and (24,7) are the foci of a conic passing through the origin then the eccentricity of conic is

Options

A386 / 12
B386 / 13
C386 / 25
D386 / 38

Correct answer

D. 386 / 38

Step-by-step solution

Distance between foci = 19^2+5^2 = 386 Now by PS + S'P = 2a (for ellipse) (take point P at origin) we get a=19 2 a e= 386 e= 386 38 If conic is hyperbola |P S-P S^ |=2 a a=6 by 2ae' = 386 e ^ = 386 12

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