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JEE Main20207 Jan 2020Evening ShiftChemistryp Block Elements (Group 15, 16, 17 & 18)Actual

In the following reactions, products A and B , respectively, are: N a O H + C l 2 → A + s i d e   p r o d u c t s h o t   a n d   c o n c . C a O H 2 + C l 2 → B + s i d e   p r o d u c t s d r y

Options

  1. AN a C l O 3 and C a O C l 2
  2. BN a C l O 3 and C a C l O 3 2
  3. CN a O C l and C a O C l 2
  4. DN a O C l and C a C l O 3 2

Correct answer

A. N a C l O 3 and C a O C l 2

Step-by-step solution

Here, NaOH gives NaClO 3 on reaction with chlorine gas. Ca OH 2 gives CaOCl 2 on reaction with chlorine gas. 6 NaOH + 3 Cl 2 hot   and   conc → NaClO 3 A + 5 NaCl + 3 H 2 O 2 Ca OH 2 dry + 2 Cl 2 → Ca OCl 2 B + CaCl 2 + 2 H 2 O Ca OCl 2 is known as bleaching powder.

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