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JEE Main 20207 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Evening Shift
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2020 · 7 January · Evening Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

In the following reactions, products (A) and (B) , respectively,...

In the following reactions, products (A)\left(A\right) and (B)\left(B\right) , respectively, are:
NaOH+Cl2→(A)+sideproductsNaOH + C{l}_{2} \to \left(A\right) + sideproducts
\left(hotandconc .\right)</p><p><br/></p><p><br />Ca{\left(OH\right)}_{2} + C{l}_{2} \to \left(B\right) + sideproducts<br/>(dry)<br />\left(dry\right)

Options

  1. A{NaClO}_{3}andandCa{\left(OCl\right)}_{2}
  2. B{NaClO}_{3}andandCa{\left({ClO}_{3}\right)}_{2}
  3. CNaOClandandCa{\left(OCl\right)}_{2}
  4. DNaOClandandCa{\left({ClO}_{3}\right)}_{2}

Correct answer

A. {NaClO}_{3}andandCa{\left(OCl\right)}_{2}

Step-by-step solution

Here,

NaOHNaOH gives NaClO3{NaClO}_{3} on reaction with chlorine gas.

Ca( OH )Ca{\left(\text{ OH }\right)}_{2}givesgives{CaOCl}_{2}onreactionwithchlorinegas.</p><p>on reaction with chlorine gas.</p><p>\mathop{6NaOH + 3{Cl}_{2}}_{\left(hotandconc\right)} \to \mathop{{NaClO}_{3}}_{A} + 5NaCl + 3{H}_{2}O\mathop{2Ca{\left(OH\right)}_{2}}_{dry} + 2{Cl}_{2} \to \mathop{Ca{\left(OCl\right)}_{2}}_{B} + {CaCl}_{2} + 2{H}_{2}O</p><p></p><p>Ca{\left(OCl\right)}_{2} is known as bleaching powder.

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