Chlorine reacts with hot and concentrated NaOH and produces compounds (X) and (Y). Compound (X) gives white precipitate with silver nitrate solution. The average bond order between Cl and O atoms in (Y) is

Correct answer: 0 3C l _ 2 + array ll 6NaOH Hot and conc . array → array ll 5NaCl (X) array + array ll NaCl O _ 3 (Y) array + 3 H _ 2 O NaCl + AgN O _ 3 → AgCl + NaN O _ 3 whiteppt Y is NaCI O _ 3 Cl O _ 3 ^ - (bond order) = (5)/(3) = 1.67 .

JEE Main 20207 JanuaryMorning Shift

Exam: JEE Main
Year: 2020
Date: 7 January
Shift: Morning Shift
Subject: Chemistry
Chapter: p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2020 · 7 January · Morning Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

Chlorine reacts with hot and concentrated NaOH and produces...

Chlorine reacts with hot and concentrated

NaOH

and produces compounds \left(X\right) and \left(Y\right). Compound \left(X\right) gives white precipitate with silver nitrate solution. The average bond order between

Cl and O

atoms in \left(Y\right) is _______________.

Correct answer

Step-by-step solution

3C{l}_{2} +

\begin{array}{ll}6NaOH \\ Hot \text{ and } conc .\end{array}

\to

\begin{array}{ll}5NaCl \\ \left(X\right)\end{array}

+

\begin{array}{ll}NaCl{O}_{3} \\ \left(Y\right)\end{array}

+ 3{H}_{2}O

NaCl + AgN{O}_{3} \to AgCl + NaN{O}_{3}whiteppt

Y

NaCI{O}_{3}

Cl{O}_{3}^{-}

(bond order)

= \dfrac{5}{3} = 1.67

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