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JEE Main 20199 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
9 April
Shift
Morning Shift
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2019 · 9 April · Morning Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The correct order of the oxidation states of nitrogen in NO, N _ 2...

The correct order of the oxidation states of nitrogen in NO,N2O,NO2NO, {N}_{2}O, N{O}_{2} and N2O3{N}_{2}{O}_{3} is

Options

  1. AN2O<NO<N2O3<NO2{N}_{2}O < NO < {N}_{2}{O}_{3} < N{O}_{2}
  2. BNO2<N2O3<NO<N2ON{O}_{2} < {N}_{2}{O}_{3} < NO < {N}_{2}O
  3. CNO2<NO<N2O3<N2ON{O}_{2} < NO < {N}_{2}{O}_{3} < {N}_{2}O
  4. DN2O<N2O3<NO<NO2{N}_{2}O < {N}_{2}{O}_{3} < NO < N{O}_{2}

Correct answer

A. N2O<NO<N2O3<NO2{N}_{2}O < NO < {N}_{2}{O}_{3} < N{O}_{2}

Step-by-step solution

Oxidation states of following
N2O⇒2x+1(−2)=0⇒x=1{N}_{2}O ⇒ 2x + 1\left(- 2\right) = 0 ⇒ x = 1
NO⇒x+1(−2)=0⇒x=2NO ⇒ x + 1\left(- 2\right) = 0 ⇒ x = 2
N2O3⇒2x+3(−2)=0⇒x=3{N}_{2}{O}_{3} ⇒ 2x + 3\left(- 2\right) = 0 ⇒ x = 3
NO2⇒x+2(−2)=0⇒x=4N{O}_{2} ⇒ x + 2\left(- 2\right) = 0 ⇒ x = 4
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