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JEE Main 20198 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2019 · 8 April · Evening Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:

The ion that has sp3d2{sp}^{3}{d}^{2} hybridization for the central atom is:The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:

Options

  1. A{\left[{BrF}_{2}\right]}^{-}
  2. B{\left[I{Cl}_{4}\right]}^{-}
  3. C{\left[I{F}_{6}\right]}^{-}
  4. D{\left[I{Cl}_{2}\right]}^{-}

Correct answer

B. {\left[I{Cl}_{4}\right]}^{-}

Step-by-step solution

The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:
Steric number =σ+lp=4+2;sp3d2= \sigma + lp= 4 + 2;sp^{3}d^{2} hybridized

The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:
Steric number =σ+lp=2+3=5;sp3d= \sigma + lp= 2 + 3 = 5;sp^{3}d hybridized

The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:
Steric number =σ+lp=6+1=7;sp3d3= \sigma + lp= 6 + 1 = 7;sp^{3}d^{3} hybridized

The ion that has sp ^ 3 d ^ 2 hybridization for the central atom is:
Steric number =σ+lp=2+3=5;sp3d= \sigma + lp= 2 + 3 = 5;sp^{3}d hybridized

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