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JEE Main 20198 AprilEvening Shift

Exam: JEE Main
Year: 2019
Date: 8 April
Shift: Evening Shift
Subject: Chemistry
Chapter: p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2019 · 8 April · Evening Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The correct statement about I Cl _ 5 and I Cl _ 4 ^ - is:

The correct statement about

I{Cl}_{5}

and

I{Cl}_{4}^{-}

is:

The correct statement about I Cl _ 5 and I Cl _ 4 ^ - is:

The correct statement about I Cl _ 5 and I Cl _ 4 ^ - is:

Options

A $I{Cl}_{5}$ is trigonal bipyramidal and $I{Cl}_{4}^{-}$ is tetrahedral.
BBoth are isostructural.
C $I{Cl}_{5}$ is square pyramidal and $I{Cl}_{4}^{-}$ is tetrahedral.
D $I{Cl}_{5}$ is square pyramidal and $I{Cl}_{4}^{-}$ is square planar.

Correct answer

D. $I{Cl}_{5}$ is square pyramidal and $I{Cl}_{4}^{-}$ is square planar.

Step-by-step solution

${\left[IC{l}_{4}\right]}^{-} = lp + bp = 2 + 4 = s{p}^{3}{d}^{2}$

The correct statement about I Cl _ 5 and I Cl _ 4 ^ - is:

Square planar

$IC{l}_{5} = 1lp + 5bp = 6 = s{p}^{3}{d}^{2}$

The correct statement about I Cl _ 5 and I Cl _ 4 ^ - is:

Square pyramidal.

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