A compound A B has a rock salt structure with A: B=1: 1 . The formula weight of A B is 6.023 Y amu. And the closest distance between A and B is Y^ 1 / 3 ~nm . The observed density of the lattice in kg / m^3 is :

Correct answer: 5 aligned & A=2 y^ 1 / 3 ~nm . M=6.023 × y × 4 amu & Density =m / a^3= 6.023 × 4 × 1.66 × 10^ -27 8 y × 10^ -27 ~kg / m^3 & =(40)/(8)=5 ~kg / m^3 aligned

JEE Advanced

Exam: JEE Advanced
Subject: Chemistry
Chapter: Solid State

JEE Advanced · Chemistry · Solid State

A compound A B has a rock salt structure with A: B=1: 1 . The...

A

compound

A B

has a rock salt structure with

A: B=1: 1

. The formula weight of

A B

6.023 Y

amu. And the closest distance between

A

and

B

Y^{1 / 3} \mathrm{~nm}

. The observed density of the lattice in

\mathrm{kg} / \mathrm{m}^3

is :

Correct answer

Step-by-step solution

\begin{aligned} & A=2 y^{1 / 3} \mathrm{~nm} . \quad \mathrm{M}=6.023 \times \mathrm{y} \times 4 \mathrm{amu} \\ & \text { Density }=\mathrm{m} / \mathrm{a}^3=\frac{6.023 \times 4 \times 1.66 \times 10^{-27}}{8 \mathrm{y} \times 10^{-27}} \mathrm{~kg} / \mathrm{m}^3 \\ & =\frac{40}{8}=5 \mathrm{~kg} / \mathrm{m}^3 \end{aligned}

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