Most Important Selected Qs for JEE AdvancedChemistrySome Basic Concepts of Chemistry
A 50 ml 1.92 %( ~W / V ) solution of a metal ion M ^ nt (atomic weight =60 ) was treated with 5.332 g hydrazinehydrate ( 90 % pure) and mixture was saturated with CO ₂ gas when entire metal gets precipitated as a complex [ M ( H ₂ ~N - NHCOO )_n ] . The complex was filtered off and the filtrate was titrated with M 10 KIO ₃ in the presence of conc. HCl according to the following equation: N ₂ H ₄+ IO ₃⁻+2 H ⁺+2 Cl ⁻ I
Correct answer
3
Step-by-step solution
aligned & n _ M ⁺ = 1.92 2 60 ~mol =0.016 ~mol & n _ hydrazinehydrate == 0.9 5.332 50 ~mol =0.096 ~mol aligned n _ eqKIO3 =4 1 10 ~N 0.48 ~L =0.192 n _ eqhydrazine reacted with KIO ₃ n _ hydrazine left after reaction with M ^ n + = 0.192 4 ~mol =0.048 ~mol n _ hydrazine reacted with M ^ n+ =(0.096-0.048) mol =0.048 ~mol n _ m ⁺ n _ hydrazine = 1 n = 0.016 0.048 = 1 3