JEE Advanced
- Exam
- JEE Advanced
- Subject
- Chemistry
- Chapter
- Solid State
JEE Advanced · Chemistry · Solid State
Paragraph: In a cubic unit cell, atoms (A) are present at all...
Paragraph:
In a cubic unit cell, atoms (A) are present at all corners, (B) are present at alternate face centre and all edge centres. Atoms (C) are present at face centres left from (B) and one at each body diagonal at distance of of body diagonal from corner.Question:
An axis is passed from the given unit cell connecting opposite face centres and all atoms touching the axis are removed. The possible formula of compound left is
Options
- A or
- B or
- C or
- D or
Correct answer
A. or
Step-by-step solution
If axis passes through face centre where lies, then Number of B atoms \left(\frac{1}{2} \times 2\right)=3=\mathrm{AB}_3 \mathrm{C}_6C=6-\frac{1}{2} \times 2=5\therefore=\mathrm{AB}_4 \mathrm{C}_5