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When a salt is treated with sodium hydroxide solution it gives gas X . On passing gas X through reagent Y a brown coloured precipitate is formed. X and Y respectively, are

Options

  1. AX = NH ₃ and Y = HgO
  2. BX = NH ₃ and Y = K ₂ HgI ₄+ KOH
  3. CX = NH ₄ Cl and Y = KOH
  4. DX = HCl and Y = NH ₄ Cl

Correct answer

B. X = NH ₃ and Y = K ₂ HgI ₄+ KOH

Step-by-step solution

NH ₄⁺+ NaOH H ₂ O + NH ₃ NH ₃ is identify by K ₂ [ HgI ₄ ]+ KOH

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