JEE Main 20252 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 2 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Practical Chemistry
JEE Main 2025 · 2 April · Morning Shift · Chemistry · Practical Chemistry
Choose the correct tests with respective observations. (A) (CuSO _...
Choose the correct tests with respective observations.
(A) (\mathrm{CuSO}}_{4}) (acidified with acetic acid) (+ \mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right] →) Chocolate brown precipitate.
(B) (\mathrm{FeCl}}_{3}+ \mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right] →) Prussian blue precipitate.
(C) (\mathrm{ZnCl}}_{2}+ \mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right]), neutralised with (\mathrm{NH}}_{4} ) White or bluish white precipitate.
(D) (\mathrm{MgCl}}_{2}+\mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right] →) Blue precipitate.
(E) (\mathrm{BaCl}}_{2}+\m mathrm{K}}_{4}\left[\mmathrm{Fe}(\mathrm{CN})_6\right]), neutralised with NaOH White precipitate.
Choose the correct answer from the options given below :
(A) (\mathrm{CuSO}}_{4}) (acidified with acetic acid) (+ \mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right] →) Chocolate brown precipitate.
(B) (\mathrm{FeCl}}_{3}+ \mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right] →) Prussian blue precipitate.
(C) (\mathrm{ZnCl}}_{2}+ \mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right]), neutralised with (\mathrm{NH}}_{4} ) White or bluish white precipitate.
(D) (\mathrm{MgCl}}_{2}+\mathrm{K}}_{4}\left[\mathrm{Fe}(\mathrm{CN})_6\right] →) Blue precipitate.
(E) (\mathrm{BaCl}}_{2}+\m mathrm{K}}_{4}\left[\mmathrm{Fe}(\mathrm{CN})_6\right]), neutralised with NaOH White precipitate.
Choose the correct answer from the options given below :
Options
- AA, D and E only
- BB, D and E only
- CA, B and C only
- DC, D and E only
Correct answer
C. A, B and C only
Step-by-step solution
(2 \mathrm{CuSO}_4+\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \xrightarrow{\mathrm{CH}_3 \mathrm{COOH}}\underset{\text{(Chocolate brown ppt.)}}{\mathrm{Cu}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right]+2 \mathrm{~K}_2 \mathrm{SO}_4})
(4 \mathrm{FeCl}_3+3 \mathrm{~K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \longrightarrow \underset{\text{ (Prussian Blue ppt.) }}{\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3}+12 \mathrm{KCl})
(3 \mathrm{ZnCl}_4+2 \mathrm{~K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \underset{\text{ (White or bluish white ppt.) }}{\mathrm{K}_2 \mathrm{Zn}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2}+6 \mathrm{KCl})
(4 \mathrm{FeCl}_3+3 \mathrm{~K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \longrightarrow \underset{\text{ (Prussian Blue ppt.) }}{\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3}+12 \mathrm{KCl})
(3 \mathrm{ZnCl}_4+2 \mathrm{~K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \xrightarrow{\mathrm{NH}_4 \mathrm{OH}} \underset{\text{ (White or bluish white ppt.) }}{\mathrm{K}_2 \mathrm{Zn}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_2}+6 \mathrm{KCl})