JEE Main 2024 6 April Evening Shift
Exam JEE Main
Year 2024
Date 6 April
Shift Evening Shift
Subject Chemistry
Chapter Practical Chemistry
JEE Main 2024 · 6 April · Evening Shift · Chemistry · Practical Chemistry
During the detection of acidic radical present in a salt, a student...
During the detection of acidic radical present in a salt, a student gets a pale yellow precipitate soluble with difficulty in (\mathrm{NH}_4 \mathrm{OH}) solution when sodium carbonate extract was first acidified with dil. (\mathrm{HNO}_3) and then (\mathrm{AgNO}_3) solution was added. This indicates presence of :
Options A (\mathrm{Br}^{-}) B (I \mathrm{I} I ^{-}) C (\mathrm{Cl}^{-}) D (\mathrm{CO}_3{ }^{2-})
Correct answer A. (\mathrm{Br}^{-})
Step-by-step solution
A g + + I − → A g I Yellow ppt. A g + + C l − → A g C l White ppt A g + + B r − → A g B r Pale yellow ppt \begin{array}{ll}
\mathrm{Ag}^{+}+\mathrm{I}^{-} \rightarrow \mathrm{AgI} & \text{Yellow ppt.} \\
\mathrm{Ag}^{+}+\mathrm{Cl}^{-} \rightarrow \mathrm{AgCl} & \text{White ppt} \\
\mathrm{Ag}^{+}+\mathrm{Br}^{-} \rightarrow \mathrm{AgBr} & \text{Pale yellow ppt}
\end{array} Ag + + I − → AgI Ag + + Cl − → AgCl Ag + + Br − → AgBr Yellow ppt. White ppt Pale yellow ppt
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