JEE Advanced
- Exam
- JEE Advanced
- Subject
- Chemistry
- Chapter
- p Block Elements (Group 13 & 14)
JEE Advanced · Chemistry · p Block Elements (Group 13 & 14)
Column I (X, Y, Z W are unknown products) Column II (Hybridisation...
| Column I (X, Y, Z W are unknown products) | Column II (Hybridisation of central atom in unknown product) | Column III (Characteristics of unknown product) |
| (I) | (i) s p³ | (P) Two types of bonds are present |
| between same type of bonded atoms | ||
| \begin{gathered} (II) H_3 BO_3+Na_2 CO_3 \rightarrow Y+H_2 O+CO_2 \end{gathered} | (ii) s p | (Q) Lewis acid |
| (III) | (iii) s p² | (R) Covalent Carbide |
| (IV) Si+C \xrightarrow{2200^{{}^{{}^{\circ}}} C} W | (iv) s p³ d | (S) Forms alkaline solution on hydrolysis |
Select the correct combination in which the unknown compound formed is planar
Options
- A(II), (ii), (Q)
- B(III) (ii) (Q)
- C(III) (iii) (Q)
- D(II) (iii) (R)
Correct answer
C. (III) (iii) (Q)
Step-by-step solution
Answer (C)
Correct combination is III. iii, Q