Match List I with List II. List-I (Anion) List-II (gas evolved on reaction with dil. H _ 2 SO _ 4 ) (A) CO _ 3 ^ 2 - (I) Colourless gas which turns lead acetate paper black. (B) S ^ 2 - (II) Colourless gas which turns

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Correct answer: D. A - IV, B - I, C - II, D - III

When small amount of carbonate salt is treated with dilute ${H}_{2}{SO}_{4} or dilute$ HCl $, A colourless, odourless gas \left({CO}_{2}\right)$ is evolved with brisk effervescence

When small amount of the following salts are treated with dilute ${H}_{2}{SO}_{4}$ the following observations are seen.

Carbonate salt $\left({CO}_{3}^{2 -}\right)$	Brisk effervescence of ${CO}_{2}$ gas, ${CO}_{3}^{2 -} + {H}_{2}{SO}_{4} \to {SO}_{4}^{2 -} + {H}_{2}O + {CO}_{2} ↑$
Sulphide salt \left({S}^{- 2}\right) $</td> <td style="text-align: center;">A colourless gas \left({H}_{2}S\right)$ with rotten egg smell

${Na}_{2}S + {H}_{2}{SO}_{4} \to {Na}_{2}{SO}_{4} + {H}_{2}S ↑$

NO^{2 –} on reaction with dilute H₂SO₄will give brown NO₂(g) will turn KI solution blue.

${SO}_{3}^{2 -}$ on reaction with dilute ${H}_{2}{SO}_{4}$ will give ${SO}_{2}\left(g\right), which will turn acidified potassium dichromate solution green.</p><p> </p>$

	List-I (Anion)		List-II (gas evolved on reaction with dil. ${H}_{2}{SO}_{4}$ )
(A)	${CO}_{3}^{2 -}$	(I)	Colourless gas which turns lead acetate paper black.
(B)	${S}^{2 -}$	(II)	Colourless gas which turns acidified potassium dichromate solution green.
(C)	${SO}_{3}^{2 -}$	(III)	Brown fumes which turns acidified KI solution containing starch blue.
(D)	${NO}_{2}^{-}$	(IV)	Colourless gas evolved with brisk effervescence, which turns lime water milky.

Match List I with List II. List-I (Anion) List-II (gas evolved on...

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