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JEE Main202325 Jan 2023Morning ShiftChemistrySolid StateActual

A cubic solid is made up of two elements X and Y . Atoms of X are present on every alternate corner and one at the center of cube. Y is at 1 3 rd of the total faces. The empirical formula of the compound is

Options

  1. AX 2 Y 1 . 5
  2. BX 1 . 5 Y
  3. CXY 2 . 5
  4. DX 1 . 5 Y 2

Correct answer

B. X 1 . 5 Y

Step-by-step solution

The share of the atom present at corner of the cube is 1 / 8 . The share of the atom at face centre is 1 / 2 . Hence, the molecule can be represented as follows, X 4 × 1 8 + 1 × 1 Y 6 × 1 3 × 1 2 ⇒ X 1 2 + 1    Y 1 ⇒ X 2 3    Y 1 ⇒ X 1 . 5    Y 1 (Empirical formula) ⇒ X 3    Y 2 .

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