The distance between Na + and Cl - ions in solid NaCl of density 43 . 1 g cm - 3 is . . . . . × 10 - 10 m . (Nearest Integer) (Given : N A = 6 . 02 × 10 23 mol - 1 )

Step-by-step solution

For NaCl   Z = 4 and M = 58 . 5 gram d = Z × M N A × Volume 43 . 1 = 4 × 58 . 5 6 . 02 × 10 23 × a 3 a 3 = 4 × 58 . 5 6 . 02 × 43 . 1 × 10 - 23 = 0 . 9 × 10 - 23 = 9 × 10 - 24 a = 2 . 08 × 10 - 8   cm d Na + + Cl - = a 2 = 2 . 08 × 10 - 10 2   m   ≃ 1 × 10 - 10   m