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JEE Main 20198 AprilMorning Shift

Exam: JEE Main
Year: 2019
Date: 8 April
Shift: Morning Shift
Subject: Chemistry
Chapter: Solid State

JEE Main 2019 · 8 April · Morning Shift · Chemistry · Solid State

Element B forms ccp structure and A occupies half of the octahedral...

Element

B

forms ccp structure and

A

occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

Options

A ${A}_{2}B{O}_{4}$
B $A{B}_{2}{O}_{4}$
C ${A}_{2}{B}_{2}O$
D ${A}_{4}{B}_{2}O$

Correct answer

B. $A{B}_{2}{O}_{4}$

Step-by-step solution

For ccp structure:
Number of octahedral voids are

= 4

Number of tetrahedral voids are

= 8

{Z}_{B} = 4

(number of atoms present in ccp structure)

{Z}_{A} = \dfrac{1}{2} \times 4 = 2

{Z}_{O} = 8

So formula is

{A}_{2}{B}_{4}{O}_{8} = A{B}_{2}{O}_{4} .

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