JEE Main20198 Apr 2019Morning ShiftChemistrySolid StateActual

Element B forms ccp structure and A occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

Options

AA 2 B O 4
BA B 2 O 4
CA 2 B 2 O
DA 4 B 2 O

Correct answer

B. A B 2 O 4

Step-by-step solution

For ccp structure: Number of octahedral voids are = 4 Number of tetrahedral voids are = 8 Z B = 4 (number of atoms present in ccp structure) Z A = 1 2 × 4 = 2 Z O = 8 So formula is A 2 B 4 O 8 = A B 2 O 4 .

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