JEE Main 20199 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 9 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Solid State
JEE Main 2019 · 9 January · Evening Shift · Chemistry · Solid State
At 100 ^ o C, copper (Cu) has FCC unit cell structure with cell...
At copper \left(Cu\right)FCCxÅCugc{m}^{- 3}
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
Crystal structure is so number of atoms per unit cell \left(N\right) = 4= x . {Å}^{} = x{10}^{- 8}c{m}^{3}\dfrac{ZM}{{N}_{A}{a}^{3}} = \dfrac{4 \times 63 .5}{\left(6 .03 \times {10}^{23}\right){\left(x \times {10}^{- 8}\right)}^{3}}gm / {cm}^{3}= \dfrac{4 \times 63.5}{\left(6.0\right) \times {x}^{3} \times {10}^{- 1}} = \dfrac{422}{{x}^{3}}gm / c{m}^{3} = \dfrac{422}{{x}^{3}}