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JEE Main 201323 AprilOnline
Exam
JEE Main
Year
2013
Date
23 April
Mode
Online
Subject
Chemistry
Chapter
Solid State

JEE Main 2013 · 23 April · Online · Chemistry · Solid State

In a face centred cubic lattice, atoms of A form the corner points...

In a face centred cubic lattice, atoms of A form the corner points and atoms of B form the face centred points. If two atoms of A\mathrm{A} are missing from the corner points, the formula of the ionic compound is :

Options

  1. AAB3\mathrm{AB}_3
  2. BAB4\mathrm{AB}_4
  3. CA2 B5\mathrm{A}_2 \mathrm{~B}_5
  4. DAB2\mathrm{AB}_2

Correct answer

B. AB4\mathrm{AB}_4

Step-by-step solution

A form corner points and two atoms of A are missing from corner ∴ Atoms at corner (A)=6×18=34 Atoms at face centre (B)=6×12=3∴A3/4 B3 i.e., AB4\begin{aligned} \therefore \quad& \text{ Atoms at corner }(\mathrm{A})=6 \times \frac{1}{8}=\frac{3}{4}\\ & \text{ Atoms at face centre }(\mathrm{B})=6 \times \frac{1}{2}=3 \\ \therefore & \mathrm{A}_{3/4} \mathrm{~B}_{3} \text{ i.e., } \mathrm{AB}_{4} \end{aligned}
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