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JEE Main 20127 MayOnline

Exam: JEE Main
Year: 2012
Date: 7 May
Mode: Online
Subject: Chemistry
Chapter: Solid State

JEE Main 2012 · 7 May · Online · Chemistry · Solid State

A solid has a ' b c c ' structure. If the distance of nearest...

A solid has a '

b c c

' structure. If the distance of nearest approach between two atoms is

1.73 Å

, the edge length of the cell is

Options

A $314.20 \mathrm{pm}$
B $1.41 \mathrm{pm}$
C $200 \mathrm{pm}$
D $216 \mathrm{pm}$

Correct answer

C. $200 \mathrm{pm}$

Step-by-step solution

For bcc structure d=

\frac{\sqrt{3} a}{2}

where

d=

distance between two atoms

a=

edge length

\begin{aligned}& 1.73=\frac{\sqrt{3}}{2}a \\ & a=\frac{2 \times 1.73}{\sqrt{3}}=2 Å=200 \mathrm{pm} \end{aligned}

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