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JEE Main 2011
Exam
JEE Main
Year
2011
Subject
Chemistry
Chapter
Solid State

JEE Main 2011 · Chemistry · Solid State

In a face centred cubic lattice, atom A occupies the corner...

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of BB is missing from one of the face centred points, the formula of the compound is

Options

  1. AAB2\mathrm{AB}_2
  2. BA2B3A_2 B_3
  3. CA2 B5\mathrm{A}_2 \mathrm{~B}_5
  4. DA2BA_2 B

Correct answer

C. A2 B5\mathrm{A}_2 \mathrm{~B}_5

Step-by-step solution

Effective no.of AA atoms =18×8=1=\frac{1}{8} \times 8=1 Effective no.of BB atoms =12×5=\frac{1}{2} \times 5 (One is missing) =52=\frac{5}{2} Therefore formula is A1B52=A2B5A_1 B_{\frac{5}{2}}=A_2 B_5
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