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In the reaction, 2 Al ( s )+6 HCl ( aq ) 2 Al ³⁺( aq )+6 Cl ⁻( aq )+3 H ₂( ~g )

Options

  1. A11.2 ~L H ₂( ~g ) at STP is produced for every mole of HCl consumed.
  2. B33.6 ~L H ₂( ~g ) is produced regardless of temperature and pressure for every mole of Al that reacts.
  3. C12 ~L HCl ( aq ) is consumed for every 6 ~L H ₂( ~g ) produced.
  4. D67.2 ~L H ₂( ~g ) at STP is produced for every mole of Al that reacts.

Correct answer

A. 11.2 ~L H ₂( ~g ) at STP is produced for every mole of HCl consumed.

Step-by-step solution

Reaction: 2 Al (s) + 6 HCl (aq) 2 Al ³⁺(aq) + 6 Cl ^-(aq) + 3 H ₂(g) Checking each option: (1) Per 1 mole HCl: From stoichiometry, 6 mol HCl produces 3 mol H₂, so 1 mol HCl produces 0.5 mol H₂ = 11.2 L at STP. TRUE (2) Per 1 mole Al: 2 mol Al produces 3 mol H₂, so 1 mol Al produces 1.5 mol H₂ = 33.6 L at STP only, not regardless of T and P. FALSE (3) Volume ratio at same T,P: 6 mol HCl : 3 mol H₂ = 2:1, so 12 L HCl : 6 L H₂. TRUE (4) Per 1 mole Al: 1.5 mol H₂ = 33.6 L, not 67.2 L. FALSE Option (1) is correct.

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