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JEE Main 202621 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
21 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2026 · 21 January · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

14.0 g of calcium metal is allowed to react with excess HCl at 1.0...

14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K. Which of the following statements is incorrect?
[Given : Molar mass in gmol−1\mathrm{g} \mathrm{mol}^{-1} of Ca−40,Cl−35.5,H−1\mathrm{Ca}-40, \mathrm{Cl}-35.5, \mathrm{H}-1]

Options

  1. A0.35 mol of H2\mathrm{H}_{2} gas is evolved.
  2. B7.84 L of H2\mathrm{H}_{2} gas is evolved.
  3. CThe limiting reagent is calcium metal.
  4. D33.3 g of CaCl2\mathrm{CaCl}_{2} is produced.

Correct answer

D. 33.3 g of CaCl2\mathrm{CaCl}_{2} is produced.

Step-by-step solution

Reaction: Ca+2HCl→CaCl2+H2Ca + 2HCl \rightarrow CaCl_2 + H_2
Moles of Ca = 14.040=0.35\frac{14.0}{40} = 0.35 mol. Since HCl is in excess, Ca is limiting.
Option (1): H2H_2 evolved = 0.35 mol
Option (2): Volume of H2H_2 at STP = 0.35×22.4=7.840.35 \times 22.4 = 7.84 L
Option (3): Ca is limiting reagent
Option (4): Mass of CaCl2=0.35×111=38.85CaCl_2 = 0.35 \times 111 = 38.85 g, not 33.3 g
Statement (4) is incorrect.
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