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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2025 · 4 April · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

The amount of calcium oxide produced on heating 150 kg limestone (...

The amount of calcium oxide produced on heating 150 kg limestone ( 75%75 \% pure) is ______ kg. (Nearest integer)
Given : Molar mass (in gmol−1\mathrm{g} \mathrm{mol}^{-1}) of Ca-40, O-16, C-12

Correct answer

0

Step-by-step solution

CaCO3→CaO+CO2 mass of  CaCO3=150×75100=112.5kg=112500gnCaCO3=1125So moles of CaO=1125 mass of CaO=1125×561000=63kg Correct answer ⇒63\begin{aligned} & \mathrm{CaCO}_3 \rightarrow \mathrm{CaO}+\mathrm{CO}_2 \\ & \text{ mass\text{ of } } \mathrm{CaCO}_3=\frac{150 \times 75}{100}=112.5 \mathrm{ kg} \\ & =112500 \mathrm{ g} \\ & \mathrm{n}_{\mathrm{CaCO}_3}=1125 \\ & \mathrm{So} \text{ moles of } \mathrm{CaO}=1125 \\ & \quad \text{ mass of } \mathrm{CaO}=\frac{1125 \times 56}{1000}=63 \mathrm{ kg} \\ & \text{ Correct answer } \Rightarrow 63\end{aligned}
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