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JEE Main 202523 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
23 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2025 · 23 January · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

0.01 mole of an organic compound (X) containing 10 \% hydrogen, on...

0.01 mole of an organic compound (X)(X) containing 10%10 \% hydrogen, on complete combustion produced 0.9 gH2O0.9 \mathrm{~g} \mathrm{H}_2 \mathrm{O}. Molar mass of (X)(\mathrm{X}) is _____ gmol−1\mathrm{g} \mathrm{mol}^{-1}.

Correct answer

0

Step-by-step solution

Organic compound → combustion H2O0.9gm∴\xrightarrow{\text{ combustion }} \underset{\substack{\mathrm{0.9} \mathrm{gm}}}{\mathrm{H}_2 \mathrm{O}} \therefore mole of H2O=0.918=0.05 mole∴\mathrm{H}_2 \mathrm{O}=\frac{0.9}{18}=0.05 \mathrm{~mole}\therefore mole of H in H2O=0.05×2=0.1\mathrm{H}_2 \mathrm{O}=0.05 \times 2=0.1 mole = mole of H in 0.01 mole Organic compound ∴\therefore wt of H atom in 0.01 mole compound =0.1×1=0.1gm∴=0.1 \times 1=0.1 \mathrm{gm}\therefore wt of H atom in one mole compound =0.10.01=10gm∵wt.%=\frac{0.1}{0.01}=10 \mathrm{gm}\because \mathrm{wt} . \% of H=wt. of H in one mole compound  Molar mass of compound ×1\mathrm{H}=\frac{\mathrm{wt} \text{. of } \mathrm{H} \text{ in one mole compound }}{\text{ Molar mass of compound }} \times 110=10M×100∴M=100\begin{aligned} & 10=\frac{10}{M} \times 100 \\ & \therefore M=100 \end{aligned}$$
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