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JEE Main 202522 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2025 · 22 January · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH...

20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _______ ×10−2M\times 10^{-2} \mathrm{M}. (Nearest integer)

Correct answer

0

Step-by-step solution

MF=M1V1+M2V2V1+V2=2×20+0.5×400420=0.571M=57.1×10−2M=57\begin{aligned} & M_F=\frac{M_1 V_1+M_2 V_2}{V_1+V_2} \\ & =\frac{2 \times 20+0.5 \times 400}{420}=0.571 \mathrm{M} \\ & =57.1 \times 10^{-2} \mathrm{M} \\ & =57\end{aligned}
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