JEE Main 20249 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 9 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Some Basic Concepts of Chemistry
JEE Main 2024 · 9 April · Morning Shift · Chemistry · Some Basic Concepts of Chemistry
Molarity ((M)) of an aqueous solution containing (x ~g) of anhyd....
Molarity ((\mathrm{M})) of an aqueous solution containing (x \mathrm{~g}) of anhyd. (\mathrm{CuSO}_4) in (500 \mathrm{~mL}) solution at (32{ }^{\circ} \mathrm{C}) is (2 \times 10^{-1} \mathrm{M}). Its molality will be ______ (\times 10^{-3} \mathrm{~m}). (nearest integer). [Given density of the solution (=1.25 \mathrm{~g} / \mathrm{mL})]
Correct answer
0
Step-by-step solution
\begin{aligned} & \begin{aligned} & \mathrm{M}_{\text{sol }^{\mathrm{I}}}=\mathrm{v}_{\text{sol }^{\mathrm{n}}} \times \mathrm{d}_{\text{sol }^{\mathrm{n}}} \\ &=500 \times 1.25=625 \mathrm{ g} \\ & \text{ Mass of solute }(\mathrm{x})=0.2 \times 0.5 \times 159.5 \\ & \quad=15.95\end{aligned} \\ & \mathrm{n}_{\text{solute }}=0.1, \quad \\ & \text{ Mass of solvent = Mass of solution }- \text{ Mass of solute } \\ & =625-15.95 \\ & =609.05 \\ & \mathrm{ m}=\frac{0.1}{\frac{609.05}{1000}} \\ & \mathrm{ m}=0.164=164 \times 10^{-3}\end{aligned}$