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JEE Main20245 Apr 2024Morning ShiftChemistrySome Basic Concepts of ChemistryActual

(9.3 ~g ) of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ' ( P ) '. The mass of product ' ( P ) ' obtaind is (26.4 ~g ). The percentage yield is _______ ( % ).

Correct answer

0

Step-by-step solution

93 ~g of aniline produces 330 ~g of 2,4,6- tribromoaniline. Hence 9.3 ~g of aniline should produce 33 ~g of 2, 4, 6-tribromoaniline. Hence percentage yield 26.4 100 33 =80 %

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