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JEE Main202431 Jan 2024Evening ShiftChemistrySome Basic Concepts of ChemistryActual

The molarity of 1 L orthophosphoric acid H 3 PO 4 having 70 % purity by weight (specific gravity 1 .54 g cm − 3 ) is ______ M . (Molar mass of H 3 PO 4 = 98 g mol - 1 )

Correct answer

0

Step-by-step solution

Specific gravity (density) = 1 .54 g / cc . Volume = 1 L = 1000 ml Mass of solution = 1 .54 × 1000 = 1540 g % purity of H 3 PO 4 is 70 % So weight of H 3 PO 4 = 0 .7 × 1540 = 1078 g Mole of H 3 PO 4 = mass molar mass = 1078 98 = 11 Molarity= No . of moles of solute Volume of solution in L Molarity = 11 1 L = 11 M

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