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JEE Main202313 Apr 2023Evening ShiftChemistrySome Basic Concepts of ChemistryActual

1 g of a carbonate M 2 CO 3 on treatment with excess HCl produces 0 . 01 mol of CO 2 . The molar mass of M 2 CO 3 is gmol - 1 . (Nearest integer)

Correct answer

0

Step-by-step solution

From Balanced chemical reaction, M 2 CO 3 + 2 HCl → 2 MCl + H 2 O + CO 2 Here from this, we get: 0 . 01   mol   CO 2 ≡ 0 . 01   mol   M 2 CO 3 ≡ 1   g   M 2 CO 3 We know that, Number of moles = Given   mass Molar   mass ⇒ Molar mass of M 2 CO 3 = Given   mass   of   M 2 CO 3 Number   of   Moles   of   M 2 CO 3 = 1 0 . 01 = 100   g / mol

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