The volume of hydrogen liberated at STP by treating $2 . 4g$ of magnesium with excess of hydrochloric acid is ...... $\times {10}^{- 2}L$ . Given Molar volume of gas is $22 . 4L$ at STP. Molar mass of magnesium is $24g{mol}^{- 1}$

Question

The volume of hydrogen liberated at STP by treating

2 . 4g

of magnesium with excess of hydrochloric acid is ......

\times {10}^{- 2}L

. Given Molar volume of gas is

22 . 4L

at STP. Molar mass of magnesium is

24g{mol}^{- 1}

Quantrex Academy · Accepted Answer

Correct answer: 0

The stoichiometric equation of the reaction between magnesium and hydrogen chloride can be written as follows,

One mole magnesium can liberate one mole of hydrogen gas according to the following equation.

$\mathop{Mg}_{\mathop{2 . 4g}_{= 0 . 1mole}} + 2HCl \to {MgCl}_{2} + \mathop{{H}_{2}}_{0 . 1mole}$
Volume of $1$ mole ${H}_{2}$ at $= 22 . 4L$
$∴ 0 . 1$ mole ${H}_{2}$ at STP will occupy $= 2 . 24L$

The volume of hydrogen liberated at STP by treating 2 . 4g of...

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