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JEE Main 202310 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2023 · 10 April · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

Given below are two statements: one is labelled as Assertion A and...

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: 3.1500g3 . 1500gof hydrated oxalic acid dissolved in water to make 250.0mL250 . 0mL solution will result in 0.1M0 . 1M oxalic acid solution.

Reason R: Molar mass of hydrated oxalic acid is 126gmol–1126gmo{l}^{– 1} .

In the light of the above statements, choose the correct answer from the options given below:

Options

  1. ABoth A and R are true but R is NOT the correct explanation of A
  2. BA is true but R is false
  3. CBoth A and R are true and R is the correct explanation of A
  4. DA is false but R is true

Correct answer

C. Both A and R are true and R is the correct explanation of A

Step-by-step solution

Molarity (M)=wtmwt×V×1000( M ) = \dfrac{wt}{mwt \times V} \times 1000

Using this formula, we can calculate the molarity of the oxalic acid solution as follows:

  1. Mass of hydrated oxalic acid =3.1500g= 3 . 1500g
  2. Molar mass of hydrated oxalic acid(H2C2O4⋅2H2O)( {H}_{2}{C}_{2}{O}_{4} \cdot 2{H}_{2}O )=126.064g/mol= 126 . 064g / mol
  3. Volume of the solution = 250.0mL250 . 0mL

Molarity (M)=3.15×1000126×250=0.10( M ) = \dfrac{3 . 15 \times 1000}{126 \times 250} = 0 . 10

So both assertion land reason are correct.

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