The number of molecules and moles in 2 . 8375 litres of O _ 2 at STP are respectively

Correct answer: D. 7 . 527 × 10 ^ 22 and 0 . 125mol One mole of any ideal gas occupies 22 . 7L at standard temperature and pressure. The number of moles = (Givenvolume)/(VolumeatSTP) Moles = (2 . 8375)/(22 . 7) = 0 . 125 The number of molecules = moles × N _ A Molecules = 0 . 125 × 6 . 022 × 10 ^ 23 = 7 . 527 × 10 ^ 22

JEE Main 202310 AprilMorning Shift

Exam: JEE Main
Year: 2023
Date: 10 April
Shift: Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2023 · 10 April · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

The number of molecules and moles in 2 . 8375 litres of O _ 2 at...

The number of molecules and moles in

2 . 8375

litres of

{O}_{2}

STP

are respectively

Options

A $7 . 527 \times {10}^{23}$ and $0 . 125mol$
B $7 . 527 \times {10}^{22}$ and $0 . 250mol$
C $1 . 505 \times {10}^{23}$ and $0 . 250mol$
D $7 . 527 \times {10}^{22}$ and $0 . 125mol$

Correct answer

D. $7 . 527 \times {10}^{22}$ and $0 . 125mol$

Step-by-step solution

One mole of any ideal gas occupies $22 . 7L$ at standard temperature and pressure.
The number of moles $= \dfrac{Givenvolume}{VolumeatSTP}$
Moles $= \dfrac{2 . 8375}{22 . 7} = 0 . 125$
The number of molecules $= moles \times {N}_{A}$
Molecules $= 0 . 125 \times 6 . 022 \times {10}^{23}$
$= 7 . 527 \times {10}^{22}$

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