Assume carbon burns according to following equation :
$2C ( s ) + {O}_{2} ( g ) \to 2CO\text{(s)}$
when $12g$ carbon is burnt in $48g$ of oxygen, the volume of carbon monoxide produced is $______ \times {10}^{- 1}L$ at STP [nearest integer]

Question

Assume carbon burns according to following equation :

2C ( s ) + {O}_{2} ( g ) \to 2CO\text{(s)}

when

12g

carbon is burnt in

48g

of oxygen, the volume of carbon monoxide produced is

______ \times {10}^{- 1}L

at STP [nearest integer]

Quantrex Academy · Accepted Answer

Correct answer: 0

Combustion of carbon under less supply of air,
$2C + {O}_{2} \to 2CO$ ....(X)

$\dfrac{12}{12}$ $\dfrac{48}{32}$ (Given moles of reactants)
Thus, carbon is the limiting reagent as for $1 . 5mol$ of Oxygen, 3 moles of carbon is required.

Thus, from equation(X) we get,

Mole of $CO = 1$ mole

From arrhenius law,
${\left({V}_{CO}\right)}_{atSTP} = 22 . 7Lit$

$= 227 \times {10}^{- 1}Lit$

Assume carbon burns according to following equation : 2C ( s ) + O...

Correct answer

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