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JEE Main202331 Jan 2023Evening ShiftChemistrySome Basic Concepts of ChemistryActual

Assume carbon burns according to following equation : 2 C ( s ) + O 2 ( g ) → 2 CO (s) when 12 g carbon is burnt in 48 g of oxygen, the volume of carbon monoxide produced is _ _ _ _ _ _ × 10 - 1 L at STP [nearest integer] [Given : Assume CO as ideal gas, Mass of C is 12 g mol - 1 , mass of O is 16 g mol - 1 and molar volume of an idal gas at STP is 22 . 7 L mol - 1 ]

Correct answer

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Step-by-step solution

Combustion of carbon under less supply of air, 2 C + O 2 → 2 CO ....(X) 12 12   48 32 (Given moles of reactants) Thus, carbon is the limiting reagent as for 1 . 5   mol of Oxygen, 3 moles of carbon is required. Thus, from equation(X) we get, Mole of CO = 1 mole From arrhenius law, V CO atSTP = 22 . 7 Lit = 227 × 10 - 1 Lit

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