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On complete combustion of 0 . 492 g of an organic compound containing C , H and O , 0 . 7938 g of CO 2 and 0 . 4428 g of H 2 O was produced. The % composition of oxygen in the compound is____. (Nearest Integer)

Correct answer

0

Step-by-step solution

Organic compound + O 2 ⟶     CO 2 g           +         H 2 O 0 . 7938 gram 0 . 4428 gram Weight of the organic compound= 0 . 492 gram Number of moles of CO 2 =Number of moles of C = 0 . 7938 44 Weight   of   carbon = 0 . 7938 44 12 = 0 . 216 g Weight   of   hydrogen = 0 . 4428 18 2 = 0 . 0491 g Weight   of   oxygen = 0 . 492 - 0 . 216 - 0 . 0491 = 0 . 2269 g % of O = 0 . 2249 0 . 492 × 100 = 46 . 11 ≈ 46

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