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When 800 mL of 0 . 5 M nitric acid is heated in a beaker, its volume is reduced to half and 11 . 5 g of nitric acid is evaporated. The molarity of the remaining nitric acid solution is x × 10 - 2 M . (Molar mass of nitric acid is 63 g mol - 1 )

Correct answer

0

Step-by-step solution

The number of moles of nitric acid, n HNO 3 = 0 . 5 × 0 . 8 = 0 . 4   mole n HNO 3 remains = 0 . 4 - 11 . 5 63 = 0 . 4 - 0 . 1825 = 0 . 2175 Molarity = 0 . 2175 400 × 1000 = 0 . 2175 0 . 4 = 0 . 5437   mole / lit . ≃ 0 . 54   mole / lit . = 54 × 10 - 2   mol / lit .

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