The number of N atoms in 681 g of C 7 H 5 N 3 O 6 is x × 10 21 . The value of x is N A = 6 . 02 × 10 23 mol - 1 (Nearest Integer)

Step-by-step solution

Given mass of compounds = 681   g Molar mass of C 7 H 5 N 3 O 6 = 12 × 7 + 5 × 1 + 14 × 3 + 6 × 16 = 84 + 5 + 42 + 96 = 227 Number of moles of compound = 681 227 = 3 moles Number of moles of N = 3 × number of moles of compound = 3 × 3 = 9 moles Number of atoms of N = 9 × 6 . 02 × 10 23 = 5418 × 10 21 So x = 5418