JEE Main 202224 JuneMorning Shift

Exam: JEE Main
Year: 2022
Date: 24 June
Shift: Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2022 · 24 June · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

If a rocket runs on a fuel ( C _ 15 H _ 30 ) and liquid oxygen, the...

If a rocket runs on a fuel

\left({C}_{15}{H}_{30}\right)

and liquid oxygen, the weight of oxygen required and

{CO}_{2}

released for every litre of fuel respectively are :
(Given : density of the fuel is

0 . 756g / mL

)

Options

A $1188g$ and $1296g$
B $2376g$ and $2592g$
C $2592g$ and $2376g$
D $3429g$ and $3142g$

Correct answer

C. $2592g$ and $2376g$

Step-by-step solution

density = \dfrac{mass}{volume} $mass of$ {C}_{15}{H}_{30} = d \times V = 0 . 756 \times 1000 = 756gram $$ {C}_{15}{H}_{30}\left(l\right) + \dfrac{45}{2}{O}_{2}\left(g\right) ⟶ 15{CO}_{2}\left(g\right) + 15{H}_{2}O $Molesof{C}_{15}{H}_{30} = \dfrac{756}{210}Molesof{O}_{2}used = \dfrac{45}{2}\left[\dfrac{756}{210}\right]moleMolesof{CO}_{2}formed = 15\left[\dfrac{756}{210}\right]$

${W}_{{O}_{2}} = \dfrac{45}{2}\left[\dfrac{756}{210}\right]32 = 2592gram$

${W}_{{CO}_{2}} = 2376gram$

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