JEE Main 202122 JulyMorning Shift

Exam: JEE Main
Year: 2021
Date: 22 July
Shift: Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2021 · 22 July · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

Methylation of 10g of benzene gave 9 . 2g of toluene. Calculate the...

Methylation of

10g

of benzene gave

9 . 2g

of toluene. Calculate the percentage yield of toluene (Nearest integer)

Correct answer

Step-by-step solution

${C}_{6}{H}_{6} + {CH}_{3}Cl ⟶ {C}_{6}{H}_{5}{CH}_{3} + HCl10gm\left(\dfrac{10}{78} \times 92\right)gm$
Percentage yield of toluene = $\dfrac{Actualyield}{Theoreticalyield} \times 100$

$= \dfrac{9 . 2}{920} \times 78 \times 100 = 78 %$

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