______grams of 3 - Hydroxy propanal ( MW = 74 ) must be dehydrated to produce 7 . 8g of acrolein ( MW = 56 ) ( C _ 3 H _ 4 O) if the percentage yield is 64 . (Round off to the Nearest Integer). [Given: Atomic masses: C

Correct answer: 0 Percentageyield = (Experimentalyield)/(Theoriticalyield) × 100 % yield = (7 . 8X56X100)/(x) = 64x = (7 . 8X100)/(56X64)moles W _ reactant = (780X74)/(56X64) = 16 . 11g

JEE Main 202118 MarchMorning Shift

Exam: JEE Main
Year: 2021
Date: 18 March
Shift: Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2021 · 18 March · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

______grams of 3 - Hydroxy propanal ( MW = 74 ) must be dehydrated...

______grams of

3 -

Hydroxy propanal

( MW = 74 )

must be dehydrated to produce

7 . 8g

of acrolein

( MW = 56 ) \left({C}_{3}{H}_{4}O\right)

if the percentage yield is

64 .

(Round off to the Nearest Integer).
\left[\text{Given: Atomic masses}: C: 12 . 0u, H: 1 . 0u, O: 16 . 0u\right] ______grams of 3 - Hydroxy propanal ( MW = 74 ) must be dehydrated to produce 7 . 8g of acrolein ( MW = 56 ) ( C _ 3 H

______grams of 3 - Hydroxy propanal ( MW = 74 ) must be dehydrated to produce 7 . 8g of acrolein ( MW = 56 ) ( C _ 3 H

Correct answer

Step-by-step solution

______grams of 3 - Hydroxy propanal ( MW = 74 ) must be dehydrated to produce 7 . 8g of acrolein ( MW = 56 ) ( C _ 3 H

Percentageyield = \dfrac{Experimentalyield}{Theoriticalyield} \times 100 $</p><p>$ % yield = \dfrac{7 . 8X56X100}{x} = 64x = \dfrac{7 . 8X100}{56X64}moles{W}_{reactant =}\dfrac{780X74}{56X64} = 16 . 11g

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