Consider the above reaction. The percentage yield of amide product is (Round off to the Nearest Integer). (Given : Atomic mass : C : 12 . 0 u , H : 1 . 0 u N : 14 . 0 u , O : 16 . 0 u , Cl : 35 . 5 u )

Step-by-step solution

1   mole     1   mole     1     mole = 140 . 5 gm    = 169 gm    = 273 gm ∴ 0 . 140 gm    169 140 . 5 × 0 . 140   L . R .     = 0 . 168 gm < 0 . 388 gm excess ∴ Theoretical amount of given product formed = 273 140 . 5 × 0 . 140 = 0 . 272 gm But its actual amount formed is 0 . 210 gm . Hence, the percentage yield of product. = 0 . 210 0 . 272 × 100 = 77 . 20 ≈ 77 OR Mole of Ph - CoCl = 0 . 1