1 . 86g of aniline completely reacts to form acetanilide. 10 % of...

Given $1 . 86g$

$⇒ 1mol{C}_{6}{H}_{5}{NH}_{2}$ give $1mol$

$∴$ moles of ${C}_{6}{H}_{5}{NH}_{2} =$ moles of

$⇒ \dfrac{1 . 86}{93} = \dfrac{{W}_{\text{acetanilide}}}{135}$

$⇒ {W}_{\text{acelanilide}} = \dfrac{1 . 86 \times 135}{93}g = 2 . 70g$

But efficiency of reaction is $90$ only

$∴$ Mass of acetanilide produced$= 2 . 70 \times \dfrac{90}{100}g$

$= 2 . 43g$

$= 243 \times {10}^{- 2}g$

$⇒ x = 243$