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JEE Main 20203 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
3 September
Shift
Morning Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2020 · 3 September · Morning Shift · Chemistry · Some Basic Concepts of Chemistry

The mole fraction of glucose ( C _ 6 H _ 12 O _ 6 ) in an aqueous...

The mole fraction of glucose (C6H12O6)\left({C}_{6}{H}_{12}{O}_{6}\right) in an aqueous binary solution is 0.1.0 . 1 . The mass percentage of water in it, to the nearest integer, is ………\ldots \ldots \ldots

Correct answer

0

Step-by-step solution

Let total mole of solution =1= 1

so mole of glucose =0.1= 0 . 1

mole of H2O=0.9{H}_{2}O = 0 . 9

% \left(w / w\right) of H2O=[0.9×180.9×18+0.1×180]×100{H}_{2}O = \left[\dfrac{0 . 9 \times 18}{0 . 9 \times 18 + 0 . 1 \times 180}\right] \times 100

=47.368= 47 . 368

=47.37= 47 . 37

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