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JEE Main20199 Apr 2019Morning ShiftChemistrySome Basic Concepts of ChemistryActual

For a reaction, N 2 g + 3 H 2 ( g ) ⟶ 2 N H 3 ( g ) , identify di-hydrogen ( H 2 ) as a limiting reagent in the following reaction mixtures.

Options

  1. A28 g o f N 2 + 6 g o f H 2
  2. B35 g o f N 2 + 8 g o f H 2
  3. C56 g o f N 2 + 10 g o f H 2
  4. D14 g o f N 2 + 4 g o f H 2

Correct answer

C. 56 g o f N 2 + 10 g o f H 2

Step-by-step solution

N 2 g + 3 H 2 g → 2 N H 3 g moles of  N 2 stoichiometry of  N 2 ≠ mole of  H 2 stoichiometry of  H 2 Whose ratio is less called limiting reagent. (a) mole of N 2 = 28 28 = 1 m o l e s s t i o c h i o m e t r y ratio of N 2 = 1 1 = 1 mole of H 2 = 6 2 = 3 m o l e s s t i o c h i o m e t r y ratio of H 2 = 3 3 = 1 there is no limiting reagent. (b) mole of N 2 = 35 28 = 1.25 m o l e s s t i o c h i o m e t r y ratio of N 2 = 1.25 1 limiting reagent mole of H 2 = 8 2

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