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JEE Main201912 Jan 2019Evening ShiftChemistrySome Basic Concepts of ChemistryActual

8 g of NaOH is dissolved in 18 g of H 2 O . Mole fraction of NaOH in solution and molality (in mol kg - 1 ) of the solution respectively are:

Options

  1. A0.167 , 11.11
  2. B0.167 , 22.20
  3. C0.2 , 11.11
  4. D0.2 , 22.20

Correct answer

A. 0.167 , 11.11

Step-by-step solution

n 1 = 8 40 = 0.2 n 2 = 18 18 = 1 ; n t = n 1 + n 2 = 0.2 + 1 = 1.2 Mole fraction of N a O H = n 1 n t = 0.2 1.2 = 0.167 Molality = 8 40 × 1000 18 = 11.11

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