For the following reaction, the mass of water produced from 445g of C _ 57 H _ 110 O _ 6 is: 2 C _ 57 H _ 110 O _ 6 (s) + 163 O _ 2 (g) → 114 CO _ 2 (g) + 110 H _ 2 O(l)

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Correct answer: D. 495g

C _ 57 H _ 110 O _ 6 + (163)/(2) O _ 2 → 57C O _ 2 + 55 H _ 2 O Molecular weight of C _ 57 H _ 110 O _ 6 = 890 Moles of C _ 57 H _ 110 O _ 6 = (weight(gm))/(Molecularweight) = (445)/(890) = (1)/(2) According to stoichiometry ∵ 1mole of C _ 57 H _ 110 O _ 6 gives = 55mole of H _ 2 O ∵ (1)/(2)mole of C _ 57 H _ 110 O _ 6 gives = 55 × (1)/(2)mole of H _ 2 O Wt. of H _ 2 O = mole of H _ 2 O × M Wt. of H _ 2 O = (1)/(2) × 55 × 18 = 495gm

For the following reaction, the mass of water produced from 445g of...

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