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JEE Main20199 Jan 2019Evening ShiftChemistrySome Basic Concepts of ChemistryActual

For the following reaction, the mass of water produced from 445   g   of C 57 H 110 O 6 is: 2   C 57 H 110 O 6 s + 163 O 2 g → 114   CO 2 g + 110 H 2 O l

Options

  1. A490   g
  2. B890   g
  3. C445   g
  4. D495   g

Correct answer

D. 495   g

Step-by-step solution

C 57 H 110 O 6 + 163 2 O 2 → 57 C O 2 + 55 H 2 O Molecular weight of C 57 H 110 O 6 = 890 Moles of C 57 H 110 O 6 = w e i g h t g m M o l e c u l a r   w e i g h t = 445 890 = 1 2 According to stoichiometry ∵ 1   m o l e   of C 57 H 110 O 6 gives = 55   m o l e of H 2 O ∵ 1 2   m o l e   of C 57 H 110 O 6 gives = 55 × 1 2   m o l e of H 2 O Wt. of H 2 O = mole of H 2 O × M Wt. of H 2 O = 1 2 × 55 × 18 = 495   g m

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