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An unknown chlorohydrocarbon has 3.55 % of chlorine. If each molecule of the hydrocarbon has one chlorine atom only; chlorine atoms present in 1 g of chlorohydrocarbon are :(Atomic wt. of Cl = 35 .5 u ; Avogadro constant = 6 .023 × 10 23 mol – 1 )

Options

  1. A6.023 × 10 9
  2. B6.023 × 10 23
  3. C6.023 × 10 21
  4. D6.023 × 10 20

Correct answer

D. 6.023 × 10 20

Step-by-step solution

C x H y Cl %  Cl = 3 .55 Weight of C l = 1   × 3.55 100 n C l - = 1   × 3.55 100   × 35.5 No .   of   Cl - ion =   1   ×   3 .55 100   × 35 .5 × 6 .023   × 10 23 =   6 .023   × 10 20

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