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1 gram of a carbonate M 2 CO 3 on treatment with excess HCl produces 0.01186 moles of CO 2 . The molar mass of M 2 CO 3 in gmol - 1 is:

Options

  1. A84.3
  2. B118.6
  3. C11.86
  4. D1186

Correct answer

A. 84.3

Step-by-step solution

M 2 C O 3 + 2 H C l → 2 M C l + H 2 O + C O 2 From reaction, Moles of   M 2 C O 3 = M o l e s   o f   C O 2 Weight   of   M 2 CO 3 Molar   Mass   of   M 2 CO 3   = Weight   of   CO 2 Molar   mass   of   CO 2 1 Molar   Mass   of   M 2 CO 3   = 0 . 01186   × 44 44 1 Molar   Mass   of   M 2 CO 3 = 0 .01186 Molar Mass = 1 0.01186 = 84.3 g/mol

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