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JEE Main 20169 AprilOnline
Exam
JEE Main
Year
2016
Date
9 April
Mode
Online
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2016 · 9 April · Online · Chemistry · Some Basic Concepts of Chemistry

The amount of arsenic pentasulphide that can be obtained when 35 ....

The amount of arsenic pentasulphide that can be obtained when 35.5g35 . 5g arsenic acid is treated with excess H2S{H}_{2}S in the presence of conc. HClHCl (assuming 100100 % conversion) is

Options

  1. A0.25mol0 . 25mol
  2. B0.50mol0 . 50mol
  3. C0.333mol0 . 333mol
  4. D0.125mol0 . 125mol

Correct answer

D. 0.125mol0 . 125mol

Step-by-step solution

2H3AsO4+5H2S→Conc.HClAs2S5+8H2O2{H}_{3}As{O}_{4} + 5{H}_{2}S\overset{Conc . HCl}{\to}A{s}_{2}{S}_{5} + 8{H}_{2}O

22 moles of Arsenic Acid →\to 11 mole of Arsenic Pentasulphide

11 moles of Arsenic Acid →\to 1/21 / 2 mole of Arsenic Pentasulphide

Molarmassof{H}_{3}As{O}_{4} = 141; MolarmassofA{s}_{2}{S}_{5} = 308<br/><br/><br /><br />∴NumberofmolesofNumber of moles of{H}_{3}As{O}_{4} = \dfrac{35.5}{141} = 0.25<br/><br/><br /><br />∴NumberofmolesofNumber of moles ofA{s}_{2}{S}_{5} = \dfrac{0.25}{2} = 0.125mol
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