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JEE Main 20149 AprilOnline
Exam
JEE Main
Year
2014
Date
9 April
Mode
Online
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2014 · 9 April · Online · Chemistry · Some Basic Concepts of Chemistry

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water...

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

Options

  1. A2.50 M
  2. B1.00 M
  3. C2.00 M
  4. D4.00 M

Correct answer

C. 2.00 M

Step-by-step solution

Mass of compound =120g;moles=120g60g/mole=2= 120g; moles = \dfrac{120g}{60g / mole} = 2

Mass of solution =1000+120=1120g= 1 0 0 0 + 1 2 0 = 1 1 2 0 g

Volume of solution massd=1120g1.12g/mL=1000mL\dfrac{mass}{d} = \dfrac{1120g}{1.12g / mL} = 1000mL

Molarity =2moles1000mL×1000mL= \dfrac{2 moles}{1 0 0 0 mL} \times 1 0 0 0 mL

= 2 M (no of moles/Litre)

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