JEE Main2014ChemistrySome Basic Concepts of ChemistryActual

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

Options

A2.50 M
B1.00 M
C2.00 M
D4.00 M

Correct answer

C. 2.00 M

Step-by-step solution

Mass of compound = 120 g   ;       m o l e s = 120 g 60 g / m o l e = 2 Mass of solution = 1 0 0 0 + 1 2 0 = 1 1 2 0 g Volume of solution m a s s d = 1120 g 1.12 g / m L = 1000 m L Molarity = 2 moles 1 0 0 0 mL × 1 0 0 0 mL = 2 M (no of moles/Litre)

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